xml-dev - Re: Construct a list without duplicate element

["Pete Johnston" <P.Johnston@archives.gla.ac.uk>]

Eric Riblair asked:

> Does anyone know a way to do a list in a XSL file in a ...
[query snipped]

I am not sure whether I understood your question correctly, but with 
the following XML document:

<?xml version="1.0"?>
<document>
<list>
<item colour="red">a red item</item>
<item colour="blue">a blue item</item>
<item colour="green">a green item</item>
<item colour="red">a red item</item>
<item colour="blue">a blue item</item>
<item colour="green">a green item</item>
<item colour="red">a red item</item>
</list>
</document>

and the following stylesheet

<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/XSL/Transform/1.0"
    result-ns="">

<xsl:template match="document">
<xsl:for-each select="list/item">
<xsl:sort select="@colour"/>
<xsl:variable name="x" expr="@colour"/>
<xsl:if test='not(from-preceding-siblings(*[@colour=$x]))'>
<p><xsl:value-of select="@colour"/></p>
</xsl:if>
</xsl:for-each>	 
</xsl:template>

</xsl:stylesheet>
 
XT produces the following output

<p>blue</p><p>green</p><p>red</p>

which seems to be the sort of thing you are looking for .There may be 
more elegant solutions! Your use of the order-by attribute 
suggests that you might be looking for an IE5 solution, and I doubt 
whether my offering is compatible with IE5's XSL implementation.

Pete Johnston
University of Glasgow

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