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- From: David Megginson <david@megginson.com>
- To: xml-dev@ic.ac.uk
- Date: 05 Jan 2000 10:12:59 -0500
John Aldridge <john.aldridge@informatix.co.uk> writes:
> I'm sorry, I don't see the problem. The QNames are equal if ns() and
> name() both match. The prefix is irrelevant. This is what I suggested in
> my definition of the equality operator above.
>
> if (qn1 == qn2) ...
>
> just does the right thing. If some application really wants to compare the
> prefixed name, it can always write:
>
> if (qn1.prefixedName () == qn2.prefixedName ()) ...
>
> I'm obviously missing something, since you and other knowledgable people
> don't regard this as self evidently obvious -- can you explain the problem
> to me, please?
In principle (the principle of least surprise), it's very bad
behaviour for two objects to be == in C++ or equals() in Java if any
of their publicly-accessible fields differ. Think of sets, for
example.
All the best,
David
--
David Megginson david@megginson.com
http://www.megginson.com/
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