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- From: Andrew n marshall <amarshal@zig.usc.edu>
- To: gauti@mindless.com
- Date: Fri, 30 Jun 2000 08:46:05 -0700 (PDT)
I think the position() function is getting it value from teh globabl
position in the document, as in a depth first search of the
docuemnt tree. Foreample:
1. itemlist
2. item (the first template match)
3. name
4. item (the second template match)
5. name
I don't know enough about XSLT to localize the context, but it looks like
the example under 7.7 of the spec does what you want (it uses a for-each
statemtent).
Anm
On Fri, 30 Jun 2000 gauti@mindless.com wrote:
> Hi!
>
> Can't figure out why the following xml and xsl give the output below.
>
> XML:
> <itemlist>
> <item>
> <name>AAA</name>
> </item>
> <item>
> <name>BBB</name>
> </item>
> </itemlist>
>
> XSL:
> <xsl:template match="item">
> <xsl:value-of select="position()"/>
> <xsl:value-of select="name"/>
> <p/>
> </xsl:template>
>
> OUT:
> 2AAA
> 4BBB
>
>
> Point of confusion: the position seems to start with 2 and going with an increment of 2. Is this supposed to be like this or is there a bug somewhere in my XSLT?
>
> Can anyone help?
>
> Thanks alot,
>
> Gauti
>
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