[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
Re: Define a root in a DTD
- From: David.L.Eiland@fritolay.com
- To: christine.coisy@modicon.com
- Date: Tue, 26 Jun 2001 13:34:45 -0500
christine.coisy@modicon.com wrote:
> I have few elements in a DTD and I want to explicity declare one as the
root
> to be used in XML, not the others, is there a way for that ?
As has been pointed out by others, you can't do this in the DTD. What
hasn't been mentioned is that you effectively create this constraint in
the document type declaration:
<!DOCTYPE myRoot SYSTEM "uri-of-some-dtd">
...says that this document is of type "myRoot", and thus its root/document
element is going to be one of those "myRoot" elements, a type of element
for which the content model can be found in the specified DTD.
- Mike
_____________________________________________________________________________
mike j. brown, software engineer | xml/xslt: http://skew.org/xml/
in denver, colorado, USA | personal: http://hyperreal.org/~mike/
------------------------------------------------------------------
The xml-dev list is sponsored by XML.org, an initiative of OASIS
<http://www.oasis-open.org>
The list archives are at http://lists.xml.org/archives/xml-dev/
To unsubscribe from this elist send a message with the single word
"unsubscribe" in the body to: xml-dev-request@lists.xml.org