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   Re: [xml-dev] DTD validation without a DOCTYPE

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Caro, Samuel asked:
> Is there a way to validate against a DTD if the xml file does NOT have a

Yep: add one.  For example,

    # from a Unix shell prompt:
    ( echo "<!DOCTYPE foo SYSTEM 'foo.dtd'>" ; cat mydoc.xml ) | rxp -

For a more elegant solution, if your validator supports OASIS
catalogs (nsgls does), you can set up a catalog that will choose
an appropriate DTD based on the root element type name.

	nsgmls -m /path/to/catalog -s -B *.xml

where the catalog file should contain:

	SGMLDECL xml.dcl
	DOCTYPE foo foo.dtd
	DOCTYPE bar bar.dtd

and xml.dcl specifies FEATURES IMPLYDEF DOCTYPE YES.

A suitable SGML declaration can be found, erm, here:


--Joe English



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