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   RE: [xml-dev] Simple xpath software request

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  • To: "Kris Thompson" <race@boulder.net>,<xml-dev@lists.xml.org>
  • Subject: RE: [xml-dev] Simple xpath software request
  • From: "Joshua Allen" <joshuaa@microsoft.com>
  • Date: Wed, 27 Feb 2002 23:54:46 -0800
  • Thread-index: AcHAEp0cEGD3ctEKRsm7Xz87VKF4MgAGjPog
  • Thread-topic: [xml-dev] Simple xpath software request

Well, there is an XSLT stylesheet that gives you the absolute XPath of
each node in a document:
This is standard XSLT so could be run in Xalan.  But probably even
easier if you already have a reference to a node is to just write a
function that recursively grabs the node.Parent and concats the name and
position (which is really all the XSLT is doing).

> -----Original Message-----
> From: Kris Thompson [mailto:race@boulder.net]
> Sent: Thursday, February 28, 2002 11:59 AM
> To: xml-dev@lists.xml.org
> Subject: [xml-dev] Simple xpath software request
> I must have missed it but I feel like my searching has been complete.
> am looking for a way, using one of the more popular parsers idealy
> Xerces, to if given a node in a document return the XPath string
> representation of that node.  Something like the following would be
> public static String getXPath(Document doc, Node node)
>     where node is the node that I want the XPath expression on and doc
> is the document for which this node exist.
> If this does not exist in any popular parsers than has anyone created
> this piece of code for which I could have?
> Thanks
> Kris Thompson
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