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   Re: [xml-dev] Quick filter pattern question (XSLT)

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try this:

<xsl:template match="any[contains(@ID,'typename') and 


At 05:46 PM 12/4/02 -0800, Jeff Lowery wrote:
>I've tried to find this one myself but I'm having any luck:
>If got elements that I need to distinguish by ID.  The identities are
>actually compound fields, of the format:
><any  ID="typenameX" ... >
>where X is a sequential  number.  What I want to write is this:
><xsl:template match="any[@ID="typename\n"]>
>or some such (haven't actually tried that, hmmm).  I'll check the XPath rec
>tomorrow, but maybe somebody knows off the top of their head.
>-- Jeff
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Rick Taylor
XML Developer
PPDM Association


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