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I think the OP was trying to extend a type comprising a repeating choice by
adding another branch to that choice. The base type was (a|b|c)* and he
wanted the derived type to be (a|b|c|d)*.
I'm only interpreting for him because I'm curious about the answer to that
question.
Jeff
----- Original Message -----
From: "Henry S. Thompson" <ht@cogsci.ed.ac.uk>
To: "Craig Edmunds" <craig.edmunds@comtec-europe.co.uk>
Cc: <xml-dev@lists.xml.org>
Sent: Friday, October 31, 2003 9:04 AM
Subject: Re: [xml-dev] Extending Types in xml schema
> Not entirely clear what your required functionality is.
>
> You could get flexible functionality, without multiple types being
> involved, as follows:
>
> Schema 1:
> <xs:element name="slug" abstract="true"/>
> <xs:element name="br" substitutionGroup="slug"/>
> <xs:element name="p" type="textBaseType" substitutionGroup="slug"/>
> <xs:element name="span" type="spanType" substitutionGroup="slug"/>
> <xs:element name="ul" type="ulType" substitutionGroup="slug"/>
> <xs:element name="table" type="tableType" substitutionGroup="slug"/>
> <xs:complexType name="textBaseType" mixed="true">
> <xs:element ref="slug" minOccurs="0" maxOccurs="unbounded"/>
> </xs:complexType>
>
>
> Schema 2:
>
> <xs:include schemaLocation="schema 1"/>
> <xs:element name="li" type="tableType" substitutionGroup="slug"/>
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