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>
> Looking at the interest and in reply to Michael, I am expressing my
> requirements again, in case, someone can give a refined solution.
>
> The task is to merge two xml files. Both the files have the
> same root.
> File A might or might not have node X(and its sub elements).
> File B will always have node X(and its sub elements).
>
> If File A does not contain node X:
> XSLT should get it from file B and insert it in File A under
> the defined
> location(which is not root).
>
> If File A contains node X (the location is known):
> XSLT should still get it from file B and replace the one
> existing in File A.
First let my try to rephrase your requirements using standard terminology,
to check that I have understood them correctly.
The task is to merge two XML documents. The name of the document element of
both documents is the same in both cases [but we don't use this fact].
Document A contains zero or one elements with the name X.
Document B contains exactly one element with the name X.
If document A does not contain an element named X:
the stylesheet should deep-copy the X element from document B and insert it
in Document A at a defined location.
If document A does contain an element named X:
the stylesheet should deep-copy the X element from document B and insert it
in Document A replacing the original X element.
You haven't said what "the defined location" is, but let's suppose that it's
an E element which either does or does not contain X as a child.
So, you start with an identity transform on A:
<xsl:template match="*">
<xsl:copy><xsl:copy-of select="@*"/><xsl:apply-templates/></xsl:copy>
</xsl:template>
If we hit an X, we replace it:
<xsl:template match="X">
<xsl:copy-of select="document('B.xml')//X"/>
</xsl:template>
If we hit an E that doesn't contain an X, we add the X from B:
<xsl:template match="E[not(child::X)]">
<xsl:copy><xsl:copy-of select="@*"/><xsl:apply-templates/></xsl:copy>
<xsl:copy-of select="document('B.xml')//X"/>
</xsl:template>
Michael Kay
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