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   Re: [xml-dev] choice, sequence, all: 'easy' XML Schema question

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> I believe there is no straightforward way to specify this, 

I think you can do this (dtd syntax) although whether or not that is
straightforward I leave for others to judge. (If I got this wrong, which
is possible, something not unlike this will do you what you want.

optional_element2*, 
(
 (required_element,optional_element2*,(optional_element1,optional_element2*)?) |
 (optional_element1,optional_element2*, required_element,optional_element2* )
)

obligatory comment that it's all so much easier in relax ng:-)


David

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