Re: [xml-dev] sorting elements

[Esteban Pizzini <esteban.pizzini@gmail.com>]

On 2/1/06, David Carlisle <davidc@nag.co.uk> wrote:

You didn't say what language you are using to do the sort.

I'm using xslt 1.0 :(
thank for your answer.

In XSLT2 for
example you could use something like

<xsl:stylesheet version=" 2.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:output indent="yes"/>

<xsl:template match="x">
<x>
<xsl:perform-sort select="*">
<xsl:sort select="string-join(for $i in tokenize(.,'\.') return
                                format-number(number($i),'000000'),'.')"/>
</xsl:perform-sort>
</x>
</xsl:template>

</xsl:stylesheet>


$ saxon8 srt.xml srt.xsl
<?xml version="1.0" encoding="UTF-8"?>
<x>
   <art>1</art>
   <art>1.1</art>
   <art>2</art>
   <art>2.1</art>
   <art>2.1.1</art>
</x>


Of course if your example is really representative, and all your numbers
are single digits then you don't need to split things up and rejoin, you
can just use
<xsl:sort select="."/>
which of course is also easy to do in xslt1

David


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----------------------------------------------------------------------
Esteban Pizzini
(http://mod-apache-snmp.sourceforge.net)