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- To: xml-dev@lists.xml.org
- Subject: Sending an XML DOM Document to a webService
- From: Daniele Bellucci <daniele.bellucci@gmail.com>
- Date: Tue, 21 Feb 2006 11:47:12 +0100
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Hi all,
not sure if this ML is the right place to post such a question .. please
give me a try:
i need to deploy a Java Web Service (by using the Axis Container for
Tomcat) whose aim is to publish a Class Method to recieve an XML DOM
Document, parse it and then perform some action.
I tried to define such a method in the following way:
public class MYWS {
public void getXML(Document doc) { ... }
}
the WSDL looks fine to me:
...
<wsdl:message name="getXMLRequest">
<wsdl:part name="in0" type="tns1:Element"/>
</wsdl:message>
....
but when i try to post a request with curl i get the following error:
<?xml version="1.0" encoding="UTF-8"?>
<soapenv:Envelope
xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/";
xmlns:xsd="http://www.w3.org/2001/XMLSchema";
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";>
<soapenv:Body>
<soapenv:Fault>
<faultcode>soapenv:Server.userException</faultcode>
<faultstring>org.xml.sax.SAXException: SimpleDeserializer encountered a
child element, which is NOT expected, in something it was trying to
deserialize.</faultstring><detail><ns1:hostname
xmlns:ns1="http://xml.apache.org/axis/";>wild</ns1:hostname></detail></soapenv:Fault></soapenv:Body></soapenv:Envelope>
can anyone help me?
is there any link/tutorial to explain how to code a webservice to
receive a wellformed document?
many tnx in avance
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