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try John's solution, I'm not that familiar with java.
On 6/7/06, Seetha Rama Krishna <ram_kurra@yahoo.co.in> wrote:
> Hi Anthony,
> Thanxs 4 u r reply. I tried with u r solution like
> if (!chhh.getFirstChild().getNodeValue().equals(null))
>
> {
> System.out.println("value
> exists:"+chhh.getFirstChild().getNodeValue());
> }
> else
> {
> System.out.println("value does not exist.");
> }
> But here the problem is chhh.getFirstChild().getNodeValue() is
> returing a string.
>
> Before checking for null value , the
> chhh.getFirstChild().getNodeValue() is giving null values and I am getting
> null pointer xception.
>
>
>
>
>
> Anthony Ettinger <aettinger@sdsualumni.org> wrote:
> I'm not a java programmer, but I would guess it's like most other languages
> I've used, look at the spec and see what it returns for getNodeValue();
>
> if (chhh.getFirstChild().getNodeValue()) {
>
> should be similar to this... (I use Perl here to declare a value with "my",
> but it shouldn't make any difference):
>
> if (my $value = chhh.getFirstChild().getNodeValue()) {
> print "value is: $value";
> } else {
> print "value is undefined :(";
> }
>
>
>
> if $value is not defined, it would not go into the block.
>
> However, it's up to you, but you shouldn't have to assign it to a variable
> just to check if the function returns a value, thus if (test) should work:
>
> if (chhh.getFirstChild().getNodeValue()) {
> System.out.println("value
> exists:"+chhh.getFirstChild().getNodeValue());
> } else {
> System.out.println("value does not exist.");
> }
>
>
> On 6/7/06, Seetha Rama Krishna < ram_kurra@yahoo.co.in> wrote:
> >
> > it there any method to check whether that node has node value/ not . If
> not how can i do this one??
> >
> >
> > Anthony Ettinger <aettinger@sdsualumni.org> wrote:
> >
> >
> > probably just need to check if it has a value before you do something with
> it:
> >
> > if (chhh.getFirstChild().getNodeValue()) {
> > //do a print
> > System.out.println("NodeType 1"
> +chhh.getFirstChild().getNodeValue());
> > applicationArrayList.add(chhh.getFirstChild().getNodeValue());
> > }
> >
> >
> >
> >
> > On 6/7/06, Seetha Rama Krishna wrote:
> > > Hi,
> > > I am having an xml file like the following
> > >
> > >
> >
> > > 4
> > > CLIENTDEMO
> >
> > >
> > >
> > >
> > > I had written java code to iterate thru this xml and retrieve the
> >
> > > values . when the element came I am getting null pointer
> >
> > > xception.
> > >
> > > Here is my code.
> > > NodeList application =
> > > documentElement.getElementsByTagName("application");
> > > for (int i = 0; i < application.getLength(); i++)
> > > {
> > >
> > > NodeList nl = application.item(i).getChildNodes();
> > > {
> > > Node ch = application.item(i);
> > > NodeList nll = ch.getChildNodes();
> > > ArrayList applicationArrayList = new ArrayList();
> > > for (int j = 0; j < nll.getLength(); j++)
> > > {
> > > Node chh = nl.item(j);
> > > NodeList nlll = chh.getChildNodes();
> > > //System.out.println("Animals = " + nlll.getLength());
> > >
> > > for (int k = 0; k < nlll.getLength()-1; k++)
> > > {
> > > Node chhh = nlll.item(k);
> > > System.out.println("NodeType 1"+
> > > chhh.getNodeType());
> > > if (chhh.getNodeType() == 1)
> > > {
> > > System.out.println("NodeType 1"+
> > > chhh.getNodeName ());
> > > System.out.println("NodeType 1"
> > > +chhh.getFirstChild().getNodeValue());
> > >
> > > applicationArrayList.add(chhh.getFirstChild().getNodeValue());
> > >
> > > }
> > >
> > > }
> > >
> > > }
> > >
> > >
> > > }
> > >
> > >
> > > }
> > >
> > > How can I skip when i get null values in the xml??
> > >
> > >
> > >
> > >
> > >
> > > regards,
> > > ramu
> > >
> > > Send instant messages to your online friends
> http://in.messenger.yahoo.com
> > >
> > > Stay connected with your friends even when away from PC. Link:
> > > http://in.mobile.yahoo.com/new/messenger/
> >
> >
> > --
> > Anthony Ettinger
> > Signature: http://chovy.dyndns.org/hcard.html
> >
> >
> >
> >
> >
> >
> >
> > regards,
> > ramu
> > Send instant messages to your online friends http://in.messenger.yahoo.com
> >
> > Stay connected with your friends even when away from PC. Link:
> http://in.mobile.yahoo.com/new/messenger/
>
>
>
> --
> Anthony Ettinger
> Signature: http://chovy.dyndns.org/hcard.html
>
>
>
>
> regards,
> ramu
>
> Send instant messages to your online friends http://in.messenger.yahoo.com
>
> Stay connected with your friends even when away from PC. Link:
> http://in.mobile.yahoo.com/new/messenger/
--
Anthony Ettinger
Signature: http://chovy.dyndns.org/hcard.html
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