XML.orgXML.org
FOCUS AREAS |XML-DEV |XML.org DAILY NEWSLINK |REGISTRY |RESOURCES |ABOUT
OASIS Mailing List ArchivesView the OASIS mailing list archive below
or browse/search using MarkMail.

 


Help: OASIS Mailing Lists Help | MarkMail Help

[Date Prev] | [Thread Prev] | [Thread Next] | [Date Next] -- [Date Index] | [Thread Index]
Re: [xml-dev] How to get XPath in a XSLT shylesheet

Long JingJun wrote:
> Hi all,
>
> My original target is to get the XPath to identify the location of an element in the XML output (as location attribute for an example). So that I can find the original place in the source file when I go through the generated XML output. What I mean full XPath is like this: /document/chapter[2]/section[3]/subject[1]/para[2]
>   
Heres the code we use in Schematron (I think from David Carlisle 
originally?)

   		<xsl:template match="*|@*" mode="get-full-path">

			<xsl:apply-templates select="parent::*" mode="get-full-path"/>
			<xsl:text>/</xsl:text>
			<xsl:if test="count(. | ../@*) = count(../@*)">@</xsl:if>
			<xsl:value-of select="name()"/>
			<xsl:text>[</xsl:text>
	  		<xsl:value-of select="1+count(preceding-sibling::*[name()=name(current())])"/>
	  		<xsl:text>]</xsl:text>
       	 	</xsl:template>


(XSLT question are better dealt with on the mulberry XSLT list.)

Cheers
Rick Jelliffe


[Date Prev] | [Thread Prev] | [Thread Next] | [Date Next] -- [Date Index] | [Thread Index]


News | XML in Industry | Calendar | XML Registry
Marketplace | Resources | MyXML.org | Sponsors | Privacy Statement

Copyright 1993-2007 XML.org. This site is hosted by OASIS