RE: [xml-dev] XPath on sequences of nodes

["Michael Kay" <mike@saxonica.com>]

Another suggestion: perform-sort is efficient because it creates a new
sorted sequence without actually copying the nodes. But if you created a
temporary tree in this situation, that is, if you copied the nodes to create
new nodes, then the document order of the new nodes would reflect your
sorted sequence and "/" would not disturb it. 

Michael Kay
http://www.saxonica.com/



> -----Original Message-----
> From: David Carlisle [mailto:davidc@nag.co.uk] 
> Sent: 12 January 2007 17:25
> To: gottif@iro.umontreal.ca
> Cc: xml-dev@lists.xml.org
> Subject: Re: [xml-dev] XPath on sequences of nodes
> 
> 
> 
> > For the life of me, I don't know what's happening. How can 
> a variable 
> > store 2 different results? I'd really appreciate it if 
> someone could 
> > give me a hint.
> 
> most operations on nodes, including / are defined to return 
> their reults in document order, with duplicates removed, so 
> $x/. is one way to reorder and de-duplicate a sequence for example.
> 
> You have $selectedSents/c so you reorder.
> 
> for $x in  $selectedSents return $x/c
> 
> would not reorder.
> 
> David
> 
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