XML.orgXML.org
FOCUS AREAS |XML-DEV |XML.org DAILY NEWSLINK |REGISTRY |RESOURCES |ABOUT
OASIS Mailing List ArchivesView the OASIS mailing list archive below
or browse/search using MarkMail.

 


Help: OASIS Mailing Lists Help | MarkMail Help

[Date Prev] | [Thread Prev] | [Thread Next] | [Date Next] -- [Date Index] | [Thread Index]
document identity in xpath : was RE: [xml-dev] XPath and acontinuous, uniform information space

--- David

( I am not quite sure of the later ... is doc("x" ) == doc("x") ? ) 

----- Uche

Yes.  From the XSLT 1.0 spec, 12.1:

 

Two documents are treated as the same document if they are identified by the same URI. The URI used for the comparison is the absolute URI into which any relative URI was resolved and does not include any fragment identifier. One root node is treated as the same node as another root node if the two nodes are from the same document. Thus, the following expression will always be true:

 

generate-id(document("foo.xml"))=generate-id(document("foo.xml"))

 

-----------------------

 

This was confusing me why this would be in XSLT not in XPath (i.e fn:doc() is declared in XPath so both  XSLT and XQuery can use them.

<poke>

Found it !

http://www.w3.org/TR/xpath-functions/#func-doc

 

-----------------------------

By default, this function is ·stable·. Two calls on this function return the same document node if the same URI Reference (after resolution to an absolute URI Reference) is supplied to both calls. Thus, the following expression (if it does not raise an error) will always be true:

doc("foo.xml") is doc("foo.xml")

 



[Date Prev] | [Thread Prev] | [Thread Next] | [Date Next] -- [Date Index] | [Thread Index]


News | XML in Industry | Calendar | XML Registry
Marketplace | Resources | MyXML.org | Sponsors | Privacy Statement

Copyright 1993-2007 XML.org. This site is hosted by OASIS