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Hi Folks, Problem: There are N nodes. Create an XML instance so that the nodes form a ring (cyclic) topology. Rick Jelliffe solved this problem very elegantly [1]. Here’s Rick’s solution: Arrange the nodes in document order: <Nodes> “How does that form a ring topology?” you ask. It doesn’t. Not yet. You need to define an operator on the nodes and give the operator the desired behavior (semantics). Allow me to explain. To traverse from one <Node> element to the next, you
must perform an operation. If you are moving from <Node> to <Node> using your eyes, then the operator is “physically move your eyes downward (or upward).” If you are moving from <Node> to <Node> using XPath, then the operator is following-sibling (or
preceding-sibling). Regardless of the technology, some operator must be used to move from one <Node> element to the next. Let’s generically denote that operator by
succ. To achieve our ring topology goal, then, we need to imbue the succ operator with this semantic:
The succ of a <Node> is the next node in document order Now the nodes take on a ring topology, by way of the
succ operator. Awesome! Thanks Rick!
Lesson Learned: XML has no semantics. When we define operators on the XML and imbue specific behaviors on the operators, only then we may
informally treat the XML as having semantics. Comments? /Roger |