Re: [xml-dev] XML Schema - How to define any element of type Foe

[Michael Kay <mike@saxonica.com>]

It would be nice if XSD allowed a type to be specified on a wildcard, but sadly it doesn't. I can't think of any good reason why not.

Michael Kay
Saxonica

> On 9 Mar 2017, at 09:07, cmarchand@oxiane.com wrote:
> 
> Hello,
> 
> I have a complexType definition, Foe.
> 
> In another complexType, I want to allow any child element, but require that each child element is valid against Foe definition.
> 
> Something like :
> 
> <xs:complexType name="Foe">
>  <xs:attribute name="start" type="xs:positiveInteger" use="required"/>
>  <xs:attribute name="end" type="xs:positiveInteger" use="required"/>
>  <xs:assert test="@end ge @start">
> </xs:complexType>
> 
> <xs:complexType name="parent">
>  <xs:sequence>
>    <xs:any type="Foe"/>
>  </xs:sequence>
> </xs:complexType>
> 
> How can I do this ?
> 
> Thanks,
> Christophe
> 
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