Hi Folks, If you are processing XML documents using XSLT, this is a handy thing to know. I have an XML document that consists of <row> elements: <Document> <row> <x>1</x> <y>2</y> </row> <row> <x>3</x> <y>4</y> </row> <row> <x>1</x> <y>2</y> </row> </Document> I want to eliminate duplicate rows. row[1] and row[3] have the same elements with the same values. They are duplicates. I only want one of them. I posted a question to the worldwide xsl-list and Michael Kay responded: In this situation, you can use grouping: <xsl:for-each-group select="row" group-by="x, y" composite="yes"> <xsl:sequence select="current-group()[1]"/> </xsl:for-each> Roger: Wow! That simple for-loop is doing an enormous amount of work – grouping elements by their content, iterating over the groups, selecting the first of each group (thus, deleting the duplicates). That is beautiful code. Thank you Michael. |