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[xacml] Equivalence of Functions

From: Polar Humenn <[email protected]>
To: [email protected]
Date: Mon, 23 Sep 2002 11:06:00 -0000

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Subject: [xacml] Equivalence of Functions




From: Polar Humenn <[email protected]>
To: XACML <[email protected]>
Date: Mon, 23 Sep 2002 11:04:31 -0400 (EDT)









foldr f a [] = a
foldr f a (x:xs) = ( f a ( foldr f a (x:xs) ) )

You could write sum of a bag of arguments in two ways:

sum []     = 0
sum (x:xs) = plus x (sum xs)

or

sum xs = foldr plus 0 xs

however, you can write product like this:

product xs = foldr multiply 0 xs

You get the functionality of "foldr" without having to define "product" or
"sum".


-Polar
















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