Re: How to get the 1st element in DTDD

[Bing.Li@asu.edu]

Murali,

Now I attempt to design a method to access the root in the DTD. I think it is
not hard to do that. Just String methods provided by Java can implement
it. After getting the root, a well-formed XML can be constructed according to
my program. I can show you that later if you are interested in.

Thanks for your help!
Bing

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On Fri, 22 Jun 2001, Murali Mani wrote:

> 
> Yes, doc should be initialized by an XML document, this is a wierd part of
> XML, DOCTYPE declaration comes with the XML Document, and you cannot
> specify DOCTYPE as part of the DTD.
> 
> Other things --
> I have always *very* strongly felt that the possible root elements of a
> document should be specified in the DTD/schema -- this is exactly what we
> do in regular tree grammars.
> 
> RELAX supports specification of the set of possible root elements of the
> document using export -- I am sure RELAX NG and TREX also have a similar
> feature.... XML Schema supports this in a very wierd manner -- start with
> something totally orthogonal, and use that for specifying the set of root
> elements also.
> 
> People say that the schema gives the type definitions, that is right, but
> finally we have to arrange the types as a tree, for which we need to
> specify a set of possible root elements.
> 
> Anyways, though I have always believed that the schema should specify the
> possible root types, people have always said against this, I have always
> waited for one good reason for not specifying the root of the document in
> the schema, but unfortunately, I do not think I have seen any... I will
> keep waiting for some good reason ...
> 
> Anyways, regarding your application, I think you have to assume a
> particular root element -- possibly your API might be something like --
> 
> createDocument (String name), which will then construct a document with
> name as the name of the document root element, and the document will
> conform to the DTD.
> 
> regards - murali.
> 
> On Fri, 22 Jun 2001 Bing.Li@asu.edu wrote:
> 
> > Dear Mani,
> >
> > Thanks for your help!
> >
> > But I think the doc should be initialized by an XML, right? Now I haven't an
> > XML because I need to use DTD to generate the XML. So I can't get the doc. Do
> > you think so?
> >
> > Thanks,
> > Bing
> >
> >                  _________________
> >                 |  How are you?  |_____    __
> >                 |  I am Li Bing. |     |__|  |_________
> >                 |________________| OK? |::|  | Need   /
> >                 |                \.____|::|__| Help? <
> >                 |                      \::/  \._______\
> >    /\**/\       |   ___________________________________
> >   ( o_o  )_     |__|http://www.public.asu.edu/~libing /
> >    (u--u   \_)  |  |bing.li@asu.edu, 480-829-8492(H) /
> >     (||___   )==\  |480-965-9038(L)480-965-1746(O)   \
> >   ,dP"/b/=( /P"/b\ |__________________________________\
> >   |8 || 8\=== || 8
> >   `b,  ,P  `b,  ,P
> >     """`     """`
> >
> >
> > On Fri, 22 Jun 2001, Murali Mani wrote:
> >
> > >
> > > Sorry i did not use the exact names -- i have not used xml parsers from
> > > March 2000 -- sorry for the imprecise answers --
> > >
> > > basically you have to do this --
> > >
> > > To get to the first element of the DTD -- I think you want to know what is
> > > the element specified as the root using the DOCTYPE declaration --
> > >
> > > do this --
> > >
> > > Let the Document be doc
> > >
> > > (doc.getDoctype ()).getName ()
> > >
> > > Document.getDoctype () returns DocumentType --
> > > DocumentType.getName () returns the name of the DOCTYPE declaration as a
> > > String
> > >
> > > regards - murali.
> > >
> > > Note that in xml4j 1.1.16, if I remember correctly, DTD implements
> > > DocumentType, also the method getDoctype is in the Document interface --
> > > it is not in DTD.
> > >
> > > On Fri, 22 Jun 2001 Bing.Li@asu.edu wrote:
> > >
> > > > Dear Murali,
> > > >
> > > > I didn't get the method, getDocTypeDeclaration, in the DTD class. I use IBM
> > > > XML Parser for Java 1.1.16. What about you?
> > > >
> > > > Thanks,
> > > > Bing
> > > >                  _________________
> > > >                 |  How are you?  |_____    __
> > > >                 |  I am Li Bing. |     |__|  |_________
> > > >                 |________________| OK? |::|  | Need   /
> > > >                 |                \.____|::|__| Help? <
> > > >                 |                      \::/  \._______\
> > > >    /\**/\       |   ___________________________________
> > > >   ( o_o  )_     |__|http://www.public.asu.edu/~libing /
> > > >    (u--u   \_)  |  |bing.li@asu.edu, 480-829-8492(H) /
> > > >     (||___   )==\  |480-965-9038(L)480-965-1746(O)   \
> > > >   ,dP"/b/=( /P"/b\ |__________________________________\
> > > >   |8 || 8\=== || 8
> > > >   `b,  ,P  `b,  ,P
> > > >     """`     """`
> > > >
> > > >
> > > > On Fri, 22 Jun 2001, Murali Mani wrote:
> > > >
> > > > > > I think there is something like getDocTypeDeclaration in the
> > > > interface > Document -- please check.. > > cheers - murali. > > On
> > > > Fri, 22 Jun 2001 Bing.Li@asu.edu wrote: > > > Dear all, > > > > Now I
> > > > am using DOM to generate XML files. I need to get the first
> > > element of
> > > > > > DTD.
> > > > > >
> > > > > > I am able to use
> > > > > >
> > > > > > Enumeration en = dtd.getElementDeclarations();
> > > > > >
> > > > > > to get all the elements in the DTD. But I don't know which one is the first
> > > > > > element in the DTD.
> > > > > >
> > > > > > I appreciate any help from you!
> > > > > >
> > > > > > Li Bing
> > > > > >
> > > > > >                  _________________
> > > > > >                 |  How are you?  |_____    __
> > > > > >                 |  I am Li Bing. |     |__|  |_________
> > > > > >                 |________________| OK? |::|  | Need   /
> > > > > >                 |                \.____|::|__| Help? <
> > > > > >                 |                      \::/  \._______\
> > > > > >    /\**/\       |   ___________________________________
> > > > > >   ( o_o  )_     |__|http://www.public.asu.edu/~libing /
> > > > > >    (u--u   \_)  |  |bing.li@asu.edu, 480-829-8492(H) /
> > > > > >     (||___   )==\  |480-965-9038(L)480-965-1746(O)   \
> > > > > >   ,dP"/b/=( /P"/b\ |__________________________________\
> > > > > >   |8 || 8\=== || 8
> > > > > >   `b,  ,P  `b,  ,P
> > > > > >     """`     """`
> > > > > >
> > > > > >
> > > > > >
> > > > > >
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> > > >
> > > >
> > >
> > >
> >
> >
> 
> 
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