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At 1:58 PM -0500 1/24/02, Norman Walsh wrote:
>| offers exactly the functionality you're looking for:
>|
>| public URL(URL context,
>| String spec)
>| throws MalformedURLException
>
>Uhm. I'm confused. That'll return the stream, but I actually want the
>URI to be passed through *the resolver* (for example XML Catalogs[1])
>not blindly slurped across the net.
>
No, that doesn't create a stream. It just constructs a new URL
object. If you want to get a stream (You don't have to) then you
would call openStream() on the new object.
YOu should also check out the new java.net.URI class in Java 1.4:
http://java.sun.com/j2se/1.4/docs/api/java/net/URI.html
The following methods are particularly interesting:
public URI resolve(URI uri)
public URI resolve(String uri)
These return the absolute form of the uri argument using the current
URI object as the context. Isn't this what you want?
--
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| Elliotte Rusty Harold | elharo@metalab.unc.edu | Writer/Programmer |
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| The XML Bible, 2nd Edition (Hungry Minds, 2001) |
| http://www.ibiblio.org/xml/books/bible2/ |
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