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   converting XML Schema to DTD

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I need help in converting the following schema to DTD. The schema depicts a
simple case of personnel element with fname and lname using xs:all. Pl. see
DTD generated by XML Spy does not seem to be correct.


<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema";
<xs:element name="fname" type="xs:string"/>
<xs:element name="lname" type="xs:string"/>
<xs:element name="personnel">
<xs:element ref="lname" minOccurs="0"/>
<xs:element ref="fname" minOccurs="0"/>

DTD generated by XML Spy:

<?xml version="1.0" encoding="UTF-8"?>
<!--DTD generated by XML Spy v4.2 U (http://www.xmlspy.com)-->
<!ELEMENT fname (#PCDATA)>
<!ELEMENT lname (#PCDATA)>
<!ELEMENT personnel (lname?, fname?)>

this is not correct because the XML below is INVALID with the DTD but valid
with the SCHEMA.

<?xml version="1.0" encoding="UTF-8"?>
<!--Sample XML file generated by XML Spy v4.2 U (http://www.xmlspy.com)-->
<personnel xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";


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