RE: [xml-dev] Help for finding root node from XML Schema

["Paul Spencer" <xml-dev@boynings.co.uk>]

Priti,

 

It is not possible. A document with "comment" as the root element is just as valid as one with "purchaseOrder" as the root element. This is because the philosophy of XML Schema is to validate at the element level rather than the document level.

 

I regard this side-effect of that philosophy as a weakness, others don't.

 

Others will be along shortly to tell you how their pet schema language does not have this problem.

 

Regards

 

Paul Spencer

-----Original Message-----
From: Priti Patil [mailto:ppatil@icope.com]
Sent: 10 October 2003 12:25
To: xml-dev@lists.xml.org
Subject: [xml-dev] Help for finding root node from XML Schema

Hello all,

I am new to XML and XML Schema. I am working on a project which involves visual display of XML Schema. For parsing  XML Schema I am using MSXML 4.0

 

My problem is How to get element  which will become root element of XML document which uses this schema.

 

e.g.

PO.xsd

 

<xsd:schema
     xmlns:xsd="http://www.w3.org/2001/XMLSchema"
     xmlns=""
      elementFormDefault="qualified"
      finalDefault="restriction">

 

 <xsd:element name="purchaseOrder" type="PurchaseOrderType" />

 

 <xsd:element name="comment" type="xsd:string"/>

 

 <xsd:complexType name="PurchaseOrderType">
  <xsd:sequence> ...   </xsd:sequence>
  <xsd:attribute name="orderDate" type="xsd:date"/>
 </xsd:complexType>

 

</xsd:schema>

When I parse above schema first call to get_childs returns two childs 1 ) comment 2) purchaseOrder.

 

So how to determine which is root?

 

 

 

Thanks & Regards,
 Priti Patil