Re: [xml-dev] Help for finding root node from XML Schema

["George Cristian Bina" <george@sync.ro>]

Hi,

 

XML Schema does not define a root element. You can use any of the top level elements as root element for your document.

For instance both:

 

<?xml version="1.0" encoding="UTF-8"?>
<comment xmlns="http://www.example.com/IPO"
 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xsi:schemaLocation="http://www.example.com/IPO ipo.xsd">
  ...

</comment>

 

and

 

<?xml version="1.0" encoding="UTF-8"?>
<purchaseOrder xmlns="http://www.example.com/IPO"
 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xsi:schemaLocation="http://www.example.com/IPO ipo.xsd">

    ....

</purchaseOrder>

 

are valid documents against ipo.xsd schema.

 

Regards,

 George

-------------------------------------------------------------
George Cristian Bina

<oXygen/> XML Editor - http://www.oxygenxml.com/

 

----- Original Message -----

From: Priti Patil

To: xml-dev@lists.xml.org

Sent: Friday, October 10, 2003 1:24 PM

Subject: [xml-dev] Help for finding root node from XML Schema

Hello all,

I am new to XML and XML Schema. I am working on a project which involves visual display of XML Schema. For parsing  XML Schema I am using MSXML 4.0

 

My problem is How to get element  which will become root element of XML document which uses this schema.

 

e.g.

PO.xsd

 

<xsd:schema
     xmlns:xsd="http://www.w3.org/2001/XMLSchema"
     xmlns=""
      elementFormDefault="qualified"
      finalDefault="restriction">

 

 <xsd:element name="purchaseOrder" type="PurchaseOrderType" />

 

 <xsd:element name="comment" type="xsd:string"/>

 

 <xsd:complexType name="PurchaseOrderType">
  <xsd:sequence> ...   </xsd:sequence>
  <xsd:attribute name="orderDate" type="xsd:date"/>
 </xsd:complexType>

 

</xsd:schema>

When I parse above schema first call to get_childs returns two childs 1 ) comment 2) purchaseOrder.

 

So how to determine which is root?

 

 

 

Thanks & Regards,
 Priti Patil