Re: [xml-dev] Help for finding root node from XML Schema

["Bryce K. Nielsen" <bryce@sysonyx.com>]

As they said, W3C XML Schemas can be used to validate many different XML documents. Any "top-level" or "global" <xsd:element> tag can be the document element of a valid XML document.

 

As for your project, take a look at how we're handling that with xmlArchitect (http://www.sysonyx.com/products/xmlarchitect). If the schema only has one element, our instance tree just shows that element. If it has more than one, a drop-down appears above the tree, allowing the user to select which element they consider the document element.

 

Otherwise, to avoid this in general schema-design, only have one global element, make the rest complexType or simpleType nodes. One should also note that for a schema to be valid, you have to have a least one global element (as opposed to a bunch of type nodes).

 

Bryce K. Nielsen

SysOnyx, Inc. (www.sysonyx.com)

Makers of xmlLinguist, the Text-to-XML Translator

(http://www.sysonyx.com/products/xmllinguist)

 

 

----- Original Message -----

From: Priti Patil

To: xml-dev@lists.xml.org

Sent: Friday, October 10, 2003 5:24 AM

Subject: [xml-dev] Help for finding root node from XML Schema

Hello all,

I am new to XML and XML Schema. I am working on a project which involves visual display of XML Schema. For parsing  XML Schema I am using MSXML 4.0

 

My problem is How to get element  which will become root element of XML document which uses this schema.

 

e.g.

PO.xsd

 

<xsd:schema
     xmlns:xsd="http://www.w3.org/2001/XMLSchema"
     xmlns=""
      elementFormDefault="qualified"
      finalDefault="restriction">

 

 <xsd:element name="purchaseOrder" type="PurchaseOrderType" />

 

 <xsd:element name="comment" type="xsd:string"/>

 

 <xsd:complexType name="PurchaseOrderType">
  <xsd:sequence> ...   </xsd:sequence>
  <xsd:attribute name="orderDate" type="xsd:date"/>
 </xsd:complexType>

 

</xsd:schema>

When I parse above schema first call to get_childs returns two childs 1 ) comment 2) purchaseOrder.

 

So how to determine which is root?

 

 

 

Thanks & Regards,
 Priti Patil