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   Re: [xml-dev] Help for finding root node from XML Schema

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As they said, W3C XML Schemas can be used to validate many different XML documents. Any "top-level" or "global" <xsd:element> tag can be the document element of a valid XML document.
As for your project, take a look at how we're handling that with xmlArchitect (http://www.sysonyx.com/products/xmlarchitect). If the schema only has one element, our instance tree just shows that element. If it has more than one, a drop-down appears above the tree, allowing the user to select which element they consider the document element.
Otherwise, to avoid this in general schema-design, only have one global element, make the rest complexType or simpleType nodes. One should also note that for a schema to be valid, you have to have a least one global element (as opposed to a bunch of type nodes).
Bryce K. Nielsen
SysOnyx, Inc. (www.sysonyx.com)
Makers of xmlLinguist, the Text-to-XML Translator
----- Original Message -----
Sent: Friday, October 10, 2003 5:24 AM
Subject: [xml-dev] Help for finding root node from XML Schema

Hello all,
I am new to XML and XML Schema. I am working on a project which involves visual display of XML Schema. For parsing  XML Schema I am using MSXML 4.0
My problem is How to get element  which will become root element of XML document which uses this schema.
 <xsd:element name="purchaseOrder" type="PurchaseOrderType" />
 <xsd:element name="comment" type="xsd:string"/>
 <xsd:complexType name="PurchaseOrderType">
  <xsd:sequence> ...
  <xsd:attribute name="orderDate" type="xsd:date"/>
When I parse above schema first call to get_childs returns two childs 1 ) comment 2) purchaseOrder.
So how to determine which is root?
Thanks & Regards,
 Priti Patil


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