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   RE: [xml-dev] xml, xslt and namespaces

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If you're trying to avoid the extra key strokes then I'd agree with Thomas's
answer that there is no way around it (IMHO).

However, if you're generating the XSL documents by some software and you
don't care about human readability then try this (I haven't tried it, but it
might work):

<xsl:value-of xmlns="http://www.mydomain.org/ns/"; select="request/title"/>

   Basically, define the default namespace in each and every XSLT tag where
there is an XPath expression. Cumbersome and ugly, but it's another


-----Original Message-----
From: Thomas B. Passin [mailto:tpassin@comcast.net] 
Sent: Thursday, September 16, 2004 6:49 PM
To: xml-dev
Subject: Re: [xml-dev] xml, xslt and namespaces

Mahdi Mankai wrote:

> I wonder if somebody can afford me a suitable solution for my problem.
> starting from from an original xml file that uses namespaces :
> <?xml version="1.0" encoding="UTF-8"?>
> <h:request xmlns:h="http://www.mydomain.org/ns/";>>
>    <h:title>
>        XML, XSLT and Namespaces
>    </h:title>
>      <h:message>
>        How to reference XML source namespaces in XSLT files
>    </h:message>
> </h:request>
> I want to transform it into xslt. the problem is that I dont know how to 
> resolve the original xml namespaces. 


>      <xsl:value-of select="h:request/h:title"/>
>      </b>
>      <br/>
>      <xsl:value-of select="h:request/h:message"/>
>           </body>
> </html>
> </xsl:template>
> </xsl:stylesheet>
> this solution doesn't suit me because I want to avoid rewriting the h: 
> prefix with every tag!!!

You can't really avoid having a namespace prefix in the xpath 
statements, because xpath knows nothing about any default namespaces. 
So if the elements you want to select are in a given namespace, then the 
xpath expressions must explicitly contain a prefix that puts the 
elements into that namespace.


Tom P

Thomas B. Passin
Explorer's Guide to the Semantic Web (Manning Books)

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