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XQueryX can represent any function call, the matches() function is just
another function, so it doesn't need any special support in the XQueryX
schema.
Michael Kay
http://www.saxonica.com/
> -----Original Message-----
> From: David P. Nesbitt [mailto:david_p_nesbitt@yahoo.com]
> Sent: 22 January 2005 17:41
> To: xml-dev@lists.xml.org
> Subject: RE: [xml-dev] XQueryX Schema whereClause like?
>
> Michael,
>
> Thanks for the response. However, I am interested in
> the XML Schema for XQuery. I have been using the
> whereClause element defined in this schema to
> represent a SQL where clause in XML. However, I don't
> know if it is possible to represent the SQL like
> operator using this syntax. I don't find any explicit
> support for the matches() function in the XQueryX
> schema. Is it there? Or is there someway to
> represent the 'like' operator using that schema?
>
> Regards,
> Dave
>
> --- Michael Kay <mike@saxonica.com> wrote:
>
> > The XPath 2.0 function library, which XQuery uses,
> > has a matches() function
> > that exceeds the functionality of the SQL LIKE
> > operator.
> >
> > Michael Kay
> > http://www.saxonica.com/
> >
> > > -----Original Message-----
> > > From: David P. Nesbitt
> > [mailto:david_p_nesbitt@yahoo.com]
> > > Sent: 22 January 2005 00:56
> > > To: xml-dev@lists.xml.org
> > > Subject: [xml-dev] XQueryX Schema whereClause
> > like?
> > >
> > > Does the XQueryX whereClause have an equivalent to
> > the
> > > SQL 'like' operator? I don't see that it does,
> > but I
> > > may be missing something.
> > >
> > > Regards,
> > > Dave
> > >
> > >
> > >
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