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Re: [xml-dev] XSLT Stylesheet query (newbie)
- From: Robert Koberg <rob@koberg.com>
- To: Jack Bush <netbeansfan@yahoo.com.au>
- Date: Mon, 12 Jan 2009 18:06:01 -0500
On Jan 12, 2009, at 5:53 PM, Jack Bush wrote:
> Hi All,
>
> I need some advice on how to retrieve the value of 2 attributes
> (@href, @title) in state.xml as part of transformation as follows:
>
> <?xml version="1.0" encoding="UTF-8" ?>
> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd
> ">
> - <html xmlns="http://www.w3.org/1999/xhtml"; xmlns:html="http://www.w3.org/1999/xhtml
> ">
You will most likely get better help from mulberrytech's XSL list.
AS for some hints, your content is in a namespace. You need to account
for this when you 'match' it in your XSL.
> <xsl:for-each select="/html/body/div[@id='content']/
> table[@class='sresults']/tr/td/a">
This is in no namespace. In other words, you are not targeting your
source XML.
Though I tend to almost always prefer xsl:apply-templates over xsl:for-
each, either way you need to understand what you want to 'loop' over.
How many 'a' elements exist at the path you specify?
You should probably go through soem tutorials, get Michael Kay's XSL
book for XSL 1.0 - if you really want/need to use XSL/XPath 1.0. You
would be better off starting with XSL/XPath 2.0, especially since you
are using java on the server.
best,
-Rob
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