xml-dev - XML Schemas: <all> + extension = ?

["Roger L. Costello" <costello@mitre.org>]

Hi Folks,

I am wishing to create a complexType which extends a base type.  I would
like for the resulting set of elements to be unordered (using <all>).  

Here's an example to demonstrate what I mean.  Suppose that I have a
base type called appliance, and the elements in this base type are
unordered:

<complexType name="appliance">
    <all>
        <element name="description" type="string" maxOccurs="1"/>
        <element name="warranty" type="string" maxOccurs="1"/>
    </all>
</complexType>

Now I would like to create another type, juiceAppliance, which extends
appliance.  Further, I would like for the resulting set of elements to
be unordered.  Here was my first attempt at doing this:

<complexType name="juiceAppliance" base="j:appliance" 
             derivedBy="extension">
    <all>
        <element name="name" type="string" maxOccurs="1"/>
        <element name="image" type="string" maxOccurs="1"/>
        <element name="weight" type="integer" maxOccurs="1"/>
        <element name="cost" type="decimal" maxOccurs="unbounded"/>
        <element name="retailer" type="uriReference" maxOccurs="1"/>
    </all>
</complexType> 

I realize that this does not give me what I desire. Using curly braces
to denote sets, and parenthesis to denote lists, the above produces:

({description, warranty}, {name, image, weight, cost, retailer})

which is not what I want.  My desire is that after doing the extension I
have:

{description, warranty, name, image, weight, cost, retailer}

i.e., one big set, where description and warranty come from the base
type and the rest come from juiceAppliance.  Any suggestions on how to
do this?  Thanks!  /Roger


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