Ron,
You haven't been programming C++ recently, have you?
A Java interface merely specifies a set of method signatures that any implementing class must have actual implementations of. If it implements more than one interface, then it must provide actual implementations for the _union_ of those sets - i.e., if class fooimp implements interface foo1, that just means that it must have _a_ method with signature "public void foo()". Likewise, if class fooimp implements interface foo2, that just means that it must have _a_ method with a signature "public void foo()". And if it implements both, then it still only needs to have _a_ method with that signature - not 2.
So the syntax is simply:
public class fooimp implements foo1, foo2 {
public void foo(){
...
}
}
Matthew
> -----Original Message-----
> From: Ronald Bourret [mailto:rpbourret@rpbourret.com]
> Sent: Friday, October 26, 2001 2:34 PM
> To: xml-dev
> Subject: [xml-dev] Java: interface methods with same name and
> signature
>
>
> Sorry about the non-XML topic...
>
> Suppose I have two interfaces, both of which have a method
> with the same
> name and the same signature. For example:
>
> public interface foo1 {public void foo()}
> public interface foo2 {public void foo()}
>
> Now suppose I want a single object to implement both interfaces:
>
> public class fooimp implements foo1, foo2
>
> Calling methods shouldn't be a problem, as I can cast:
>
> fooimp fi = new fooimp();
> (foo1)fi.foo();
> (foo2)fi.foo();
>
> But what is the syntax for actually implementing the methods? This is
> clearly a problem:
>
> public class fooimp implements foo1, foo2
> {
> public void foo() {...} // from foo1
> public void foo() {...} // from foo2
> }
>
> I couldn't find anything in the Java spec...
>
> Thanks,
>
> -- Ron
>
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