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   RE: [xml-dev] XML Schema: restricted <xs:any>?

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It seems that what you want is typed wildcards. However they don't exist in W3C XML Schema but substitution groups can act as a poor man's version of typed wildcards. 

________________________________

From: Scott Lamb [mailto:slamb@slamb.org]
Sent: Sun 5/4/2003 2:51 PM
To: Henry S. Thompson
Cc: xml-dev@lists.xml.org; Bryce K. Nielsen
Subject: Re: [xml-dev] XML Schema: restricted <xs:any>?




On Sunday, May 4, 2003, at 07:41 US/Central, Henry S. Thompson wrote:

> Scott Lamb <slamb@slamb.org> writes:
>> Right. I know how to set up the sequence and stuff. What I don't know
>> how to do is how to do that for arbitrary elements in other
>> namespaces. <xs:element> seems to want me tied down to a specific
>> element name. <xs:any> doesn't seem to support any of the type stuff.
>
> True, but <xs:any> can go anywhere <xs:element> can go in a content
> model, so if I've understood you correctly, just replace
>
>   <xs:element ref="other"/>
>
> in your example wiht
>
>   <xs:any namespace="##other"/>
>
> and you'll have what you want.

The definition there should be the same as the outermost one. I.e., I
want _all_ arbitrary elements in there to have the restrictions I've
laid out. If I put in any <xs:any namespace="##other"/>, I lose control
over the placement of xfp elements within it. So I want to make an
element that I can refer to that is sort of like <xs:any> and sort of
like <xs:element>. The more I look at the spec, the more I think what I
want just doesn't exist...

Thanks,
Scott


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