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Re: [xml-dev] one XML Format to other XML Format using XSLT
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In a message dated 14/06/2003 09:32:45 GMT Daylight Time, xmlbar@hotmail.com writes:
I am new to XML and in process of converting one XML format to another XML
format using XSLT. My conversion looks something as below (transforming
A.xml to B.xml)
A.xml
<Employee SBU=23>
<Name> A </Name>
<ID> 1 </ID>
<Team> XYZ </Team
</Employee>
B.xml
<Employee ID="1" Team="XYZ">
<Name> A </Name>
</Employee>
Need help to build an xsl file for this conversion ?
Thanks
Bhargav
Bhargav,
You have a couple of errors in A.xml.
Assuming those are corrected then the following stylesheet gives you the output that you described.
<?xml version='1.0'?>
<xsl:stylesheet
version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>
<xsl:output method="xml" indent="yes" encoding="UTF-8" />
<xsl:template match="/">
<xsl:apply-templates select="Employee" />
</xsl:template>
<xsl:template match="Employee">
<xsl:copy>
<xsl:attribute name="ID">
<xsl:value-of select="normalize-space(ID)" />
</xsl:attribute>
<xsl:attribute name="Team">
<xsl:value-of select="normalize-space(Team)" />
</xsl:attribute>
<xsl:copy-of select="Name" />
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
If you didn't intend the spaces in the value of the <Team> and <ID> elements you won't need the normalize-space() function in the stylesheet.
XSLT questions are normally best asked on the XSL-List.
See http://www.mulberrytech.com/xsl/xsl-list/index.html
Andrew Watt
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