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I think you can just omit the xs:all from the groups you want to compose.
Michael Kay
http://www.saxonica.com/
> -----Original Message-----
> From: Carlos Pita [mailto:carlosjosepita@yahoo.com.ar]
> Sent: 31 March 2005 14:09
> To: xml-dev@lists.xml.org
> Subject: [xml-dev] all group composition
>
> It seems as if this email has been rejected
> so I'm reposting it. Sorry if you get it twice.
> Regards,
> Carlos
>
> Hi!
>
> Is it possible to compose unordered group models
> using xml schema? I need to validate two elements
> with a lot of common children but I prefer not
> imposing any particular ordering on them. I would
> like to factorize the 80% of common children into
> an <all> group and then join them to the rest:
>
> <xs:group name="common">
> <xs:all>
> ....
> </xs:all>
> </xs:group>
>
> <xs:group name="group1">
> <xs:all>
> <xs:group ref="common"/>
> ....
> </xs:all>
> </xs:group>
>
> <xs:group name="group2">
> <xs:all>
> <xs:group ref="common"/>
> ....
> </xs:all>
> </xs:group>
>
> Of course I can't do this because <all> must be top
> level in the group and moreover it can't contain <group>.
>
> Is it possible to achieve the factorization in another way?
>
> Thank you in advance.
> Regards,
> Carlos.
>
>
>
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