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(a) You haven't said what language you think this code is written in and
what API it is using. It looks a bit like Java but I don't recognise the
classes DOMParser, XMLDocument, and XMLElement.
(b) XML is case sensitive so a search for "target" and "property" and "name"
won't find nodes named "Target" and "Property" and "NAME".
Michael Kay
http://www.saxonica.com/
> -----Original Message-----
> From: Nishi Prafull [mailto:nishiprafull@gmail.com]
> Sent: 20 April 2005 20:47
> To: xml-dev@lists.xml.org
> Subject: [xml-dev] extract the value attribute of a node in a
> xml file.
>
> Hi:
>
> I have an info.xml file containing the following
>
> <Targets AGENT_SEED="195839280">
> <Target TYPE="info_apache" DISPLAY_NAME="HTTP_Server" VERSION="2.0">
> <Property NAME="HTTPPort" VALUE="7779"/>
> </Target>
> </Targets>
>
> There will be other such <Target/> entries in the file but I need to
> only extract the value of the Property called HTTPPort using DOM
> Parser.
>
> Will the following code work -->
>
> URL info_xml_url = new URL("file://" + "/temp/info.xml");
> XMLDocument xmlDocument = null;
> NodeList nodeList = null;
>
> DOMParser parser = new DOMParser();
> parser.parse(info_xml_url);
> xmlDocument = parser.getDocument();
>
> nodeList=xmlDocument.selectNodes("/Targets//target/property");
> for(int i=0; i<nodeList.length(); i++)
> {
> if (XMLElement)nodeList.item(i).
> getAttribute("name").equals("HTTPPort")
> {
> String port_val = node.getAttribute("value");
> }
> }
>
> Please let me know.
>
> Thanks.
>
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