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Hi Bob,
Thanks for checking the example below.
I am afraid it was just used by ht to show some concept that I was
pondering and need not actually run to prove the point (it does
though, simply remove the type declaration in the elements x, y, z)
I moved the ensuing discussion to xmlschema-dev@w3.org by suggestion of ht.
Kind Regards,
Gregor
2005/4/28, Bob Foster <bob@objfac.com>:
> Hmm. XercesJ reports three errors (not warnings) from this schema of the
> form:
>
> Error - src-resolve: Cannot resolve the name 'unknownX' to a(n) 'type
> definition' component.
>
> Where X is one of: 1, 2, 3;
>
> Bob Foster
>
> Henry S. Thompson wrote:
> > I'll answer a simple question which I understand, and which I _think_
> > is what you're asking.
> >
> > The following XML document is valid:
> >
> > <!DOCTYPE root [
> > <!ELEMENT root (a|x)>
> > <!ELEMENT a (b|y)>
> > <!ELEMENT b (c|z)>
> > <!ELEMENT c EMPTY>
> > ]>
> > <root><a><b><c/></b></a></root>
> >
> > Note it contains no declarations for the elements x, y and z.
> >
> > The corresponding schema document successfully validates the same
> > instance:
> >
> > <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema";>
> > <xs:element name="root">
> > <xs:complexType>
> > <xs:choice>
> > <xs:element ref="a"/>
> > <xs:element ref="x"/>
> > </xs:choice>
> > </xs:complexType>
> > </xs:element>
> >
> > <xs:element name="a">
> > <xs:complexType>
> > <xs:choice>
> > <xs:element ref="b"/>
> > <xs:element ref="y"/>
> > </xs:choice>
> > </xs:complexType>
> > </xs:element>
> >
> > <xs:element name="b">
> > <xs:complexType>
> > <xs:choice>
> > <xs:element ref="c"/>
> > <xs:element ref="z"/>
> > </xs:choice>
> > </xs:complexType>
> > </xs:element>
> >
> > <xs:element name="c">
> > <xs:complexType/>
> > </xs:element>
> >
> > <xs:element name="x" type="unknown1"/>
> > <xs:element name="y" type="unknown2"/>
> > <xs:element name="z" type="unknown3"/>
> > </xs:schema>
> >
> > So yes, you can do incremental development of a schema for a complex
> > XML language.
> >
> > ht
>
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