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XSLT Stylesheet Exclude Parental Search Results?

Hi All,

 

I would like to extract only the content of the following mixed XML document converted from XHTML format:

 

<?xml version="1.0" encoding="UTF-8" ?>

<!DOCTYPE html (View Source for full doctype...)>

- <html xmlns="http://www.w3.org/1999/xhtml" xmlns:html="http://www.w3.org/1999/xhtml">

- <head>

- <body

.......

- ><div id="container">

+ <div id="header">

<div id="postmark" />

- <div id="content">

+ <div id="as1">

.......

<h1>Employee Detail</h1>

- <p>

<strong>Firstname:</strong>

<a >John</a>

</p>

- <p>

<strong>Surname:</strong>

<a >Smith</a>

</p>

- <p>

<strong>Date of birth:</strong>

12/01/1932

</p>

- <p>

<strong>Sex:</strong>

M

</p>

- <p>

<strong>Interest:</strong>

<br />

Tennis

<br />

Movie

<br />

.....

 

 

<?xml version="1.0" encoding="ISO-8859-1"?>

<xsl:stylesheet version="1.0"

xmlns:xsl="http://www.w3.org/1999/XSL/Transform"

xmlns:ns="http://www.w3.org/1999/xhtml"

exclude-result-prefixes="ns">

<xsl:template match="/">

<area>

<xsl:if test="/ns:html/ns:body/ns:div[@id='content']/ns:p/ns:strong">

<xsl:choose>

<xsl:when test="contains(.,'Firstname:')">

<firstname><xsl:value-of select="."/></firstname>

</xsl:when>

<xsl:otherwise>

<firstname>Unknown</firstname>

</xsl:otherwise>

</xsl:choose>

</xsl:if>

</area>

</xsl:template>

</xsl:stylesheet>

 

Not only did XSLT returned all the correct employee data but also included a lot of irrelvant data from the parental nodes as well. In other word, it return the contents from ns:html, ns:body, ns:div[@id='content'], ns:p, ns:strong which I don't want. Is there a way to prevent (exclude/mask) all these ancestral data from being included and only pick up the data in /ns:html/ns:body/ns:div[@id='content']/ns:p/ns:strong cleanly?

 

Many thanks,

Jack



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