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RE: DTD and Illegal Construct

Honestly, I'm not playing stump the experts, but what about the instance?

((A, B, D?) | (A?, B, C?, D?, E))

In this instance 'C' can only be present if 'E' is present.


-----Original Message-----
<!ELEMENT Request ((A, B, C?) | (A?, B, C?, D))> becomes

<!ELEMENT Request ((A, B, C?, D?) | (B, C?, D))>