[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
Re: DTD and Illegal Construct
- From: Dan Vint <dvint@slip.net>
- To: Jim.Shain@alltel.com (Jim Shain)
- Date: Wed, 10 Jan 2001 15:26:46 -0800 (PST)
Its the fact you have 2 different models (A, B, D?) and the other (A?, B, C? ...)
that says if i have an A which one of these two models am I using? It could be
either one - it doesn't have anything to do with the other elements in the models. B has the same problem and so does D.
..dan
>
> Honestly, I'm not playing stump the experts, but what about the instance?
>
> ((A, B, D?) | (A?, B, C?, D?, E))
>
> In this instance 'C' can only be present if 'E' is present.
>
> -Jim
>
> -----Original Message-----
> (Excerpt)
> <!ELEMENT Request ((A, B, C?) | (A?, B, C?, D))> becomes
>
> <!ELEMENT Request ((A, B, C?, D?) | (B, C?, D))>
>