Re: an xpath/xsl question: why must (a QName in an) argument be a pathexpression?

[Matt Sergeant <matt@sergeant.org>]

On Thu, 8 Mar 2001, james anderson wrote:

> 
> Yes. I admit, I did use an example from a dated xsl description. Please
> do not be misled by the details.
> 
> The question remains, is it intended, that a QName never appear in an
> argument list as such? The XPath grammar says only
> 
> [16] FunctionCall ::= FunctionName '(' ( Argument ( ',' Argument )* )? ')'
> [17] Argument ::= Expr
> 
> which subsumes a QName in the following forms only
> 
> [35] FunctionName ::= QName - NodeType 
> [36] VariableReference ::= '$' QName
> [37] NameTest ::= '*' | NCName ':' '*' | QName
> 
> Am I missing something?

The fact that NameTest can be a QName?

example, function(qname, qname), in XML::XPath parses to:

(function((child::qname),(child::qname)))

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